What are the solutions to the equation 2x^2+2x-40=0 ?

The solutions to the equation 2x^2+2x-40=0 are x=4,x=-5

Find the zeros of 2x^2+2x-40=0

The zeros of 2x^2+2x-40=0 are x=4,x=-5

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2 x^{2} + 2 x - 40 = 0

x = 4, x = - 5

Solution steps

2 x^{2} + 2 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 40) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 2}, x_{2} = \frac{- 2 - 18}{2 \cdot 2}

x = \frac{- 2 + 18}{2 \cdot 2} : 4

x = \frac{- 2 - 18}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

6 + 2 i

- 5 x^{4} - 55 x^{3} + 60 x^{2}

2 x + 18 - 1 = 33

x^{2} - 14 x + 45

x + 3 > 20 - x

What are the solutions to the equation 2x^2+2x-40=0 ?
The solutions to the equation 2x^2+2x-40=0 are x=4,x=-5
Find the zeros of 2x^2+2x-40=0
The zeros of 2x^2+2x-40=0 are x=4,x=-5