What are the solutions to the equation -11x-40+2x^2=0 ?

The solutions to the equation -11x-40+2x^2=0 are x=8,x=-5/2

Find the zeros of -11x-40+2x^2=0

The zeros of -11x-40+2x^2=0 are x=8,x=-5/2

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- 11 x - 40 + 2 x^{2} = 0

x = 8, x = - \frac{5}{2}

Decimal Notation

x = 8, x = - 2.5

Solution steps

- 11 x - 40 + 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 11 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 40) = 21

x_{1, 2} = \frac{- ( - 11 ) \pm 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 21}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 21}{2 \cdot 2}

x = \frac{- ( - 11 ) + 21}{2 \cdot 2} : 8

x = \frac{- ( - 11 ) - 21}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{5}{2}

3 x + 8 < 2 x + 10

s^{5} + 52 s^{4} + s^{3}

x^{2} - 36 = 0

3 x - 8 = x + 8

(2 x - 1)^{2} + (1 - x)^{2} = 3

What are the solutions to the equation -11x-40+2x^2=0 ?
The solutions to the equation -11x-40+2x^2=0 are x=8,x=-5/2
Find the zeros of -11x-40+2x^2=0
The zeros of -11x-40+2x^2=0 are x=8,x=-5/2