What are the solutions to the equation (3x+4)^2=5 ?

The solutions to the equation (3x+4)^2=5 are x=(sqrt(5)-4)/3 ,x=(-sqrt(5)-4)/3

Find the zeros of (3x+4)^2=5

The zeros of (3x+4)^2=5 are x=(sqrt(5)-4)/3 ,x=(-sqrt(5)-4)/3

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(3 x + 4)^{2} = 5

x = \frac{5 - 4}{3}, x = \frac{- 5 - 4}{3}

Decimal Notation

x = - 0.58797 \dots, x = - 2.07868 \dots

Solution steps

(3 x + 4)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 5 : x = \frac{5 - 4}{3}

Solve

3 x + 4 = - 5 : x = \frac{- 5 - 4}{3}

The solutions to the quadratic equation are:

x = \frac{5 - 4}{3}, x = \frac{- 5 - 4}{3}

(4 x + 5) (x + 1) = 0

ln (4) = x

4 m^{2} - 4 m + 1

lo g_{3} (5)

\frac{3 m ^{- 3} r ^{4} p ^{2}}{12 t ^{4}}

What are the solutions to the equation (3x+4)^2=5 ?
The solutions to the equation (3x+4)^2=5 are x=(sqrt(5)-4)/3 ,x=(-sqrt(5)-4)/3
Find the zeros of (3x+4)^2=5
The zeros of (3x+4)^2=5 are x=(sqrt(5)-4)/3 ,x=(-sqrt(5)-4)/3