What are the solutions to the equation t^2+10t+25=0 ?

The solutions to the equation t^2+10t+25=0 are t=-5

Find the zeros of t^2+10t+25=0

The zeros of t^2+10t+25=0 are t=-5

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t^{2} + 10 t + 25 = 0

t = - 5

Solution steps

t^{2} + 10 t + 25 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

t_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

t = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

t = - 5

The solution to the quadratic equation is:

t = - 5

∣ 2 x - 1 ∣ > ∣ x + 1 ∣ + 2

4 a^{2} b^{2} - 9 c^{2}

- 6 (x - 4)^{2} = - 54

5 k^{2} = 60 - 20 k

What are the solutions to the equation t^2+10t+25=0 ?
The solutions to the equation t^2+10t+25=0 are t=-5
Find the zeros of t^2+10t+25=0
The zeros of t^2+10t+25=0 are t=-5