What are the solutions to the equation x^2-3x-18=0 ?

The solutions to the equation x^2-3x-18=0 are x=6,x=-3

Find the zeros of x^2-3x-18=0

The zeros of x^2-3x-18=0 are x=6,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x - 18 = 0

x = 6, x = - 3

Solution steps

x^{2} - 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

x = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

x = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

12 x^{2} - 5 x - 2

(9 x - 4) = (12 - 55)

(1.5)^{2}

\frac{3}{5} x - 0 = 1

y^{2} - 3 y - 4 = 0

What are the solutions to the equation x^2-3x-18=0 ?
The solutions to the equation x^2-3x-18=0 are x=6,x=-3
Find the zeros of x^2-3x-18=0
The zeros of x^2-3x-18=0 are x=6,x=-3