What is (2^n*9^{2n+1})/(6^{n-2)} ?

The solution to (2^n*9^{2n+1})/(6^{n-2)} is 4*3^{3n+4}

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simplify (2^n*9^{2n+1})/(6^{n-2)}

simplify

\frac{2 ^{n} \cdot 9 ^{2 n + 1}}{6 ^{n - 2}}

4 \cdot 3^{3 n + 4}

Solution steps

\frac{2 ^{n} \cdot 9 ^{2 n + 1}}{6 ^{n - 2}}

Factor

6^{n - 2} : 2^{n - 2} \cdot 3^{n - 2}

= \frac{2 ^{n} \cdot 9 ^{2 n + 1}}{2 ^{n - 2} \cdot 3 ^{n - 2}}

Simplify

\frac{2 ^{n}}{2 ^{n - 2}} : 2^{2}

= \frac{2 ^{2} \cdot 9 ^{2 n + 1}}{3 ^{n - 2}}

Factor

9^{2 n + 1} : 3^{2 (2 n + 1)}

= \frac{2 ^{2} \cdot 3 ^{2 (2 n + 1)}}{3 ^{n - 2}}

Simplify

\frac{3 ^{2 (2 n + 1)}}{3 ^{n - 2}} : 3^{3 n + 4}

= 2^{2} \cdot 3^{3 n + 4}

2^{2} = 4

= 4 \cdot 3^{3 n + 4}

2 e^{- 5}

0.0 1^{2 x + 1} \geq 0. 1^{x - 4}

(3 - i)^{2}

(x - 7) (x (x - 1) - 30)

112 \geq b + 128

What is (2^n*9^{2n+1})/(6^{n-2)} ?
The solution to (2^n*9^{2n+1})/(6^{n-2)} is 4*3^{3n+4}