What is factor (5x+2)^2-(3x-4)^2 ?

The solution to factor (5x+2)^2-(3x-4)^2 is 4(4x-1)(x+3)

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factor (5x+2)^2-(3x-4)^2

factor

(5 x + 2)^{2} - (3 x - 4)^{2}

4 (4 x - 1) (x + 3)

Solution steps

(5 x + 2)^{2} - (3 x - 4)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x + 2)^{2} - (3 x - 4)^{2} = ((5 x + 2) + (3 x - 4)) ((5 x + 2) - (3 x - 4))

= ((5 x + 2) + (3 x - 4)) ((5 x + 2) - (3 x - 4))

Simplify

((5 x + 2) + (3 x - 4)) ((5 x + 2) - (3 x - 4)) : (8 x - 2) (2 x + 6)

= (8 x - 2) (2 x + 6)

Factor

8 x - 2 : 2 (4 x - 1)

Factor

2 x + 6 : 2 (x + 3)

= 2 (4 x - 1) \cdot 2 (x + 3)

Multiply the numbers:

2 \cdot 2 = 4

= 4 (4 x - 1) (x + 3)

6 a^{4} b - 10 a^{3} b^{2} - 6 a^{2} b^{3}

2 s + 5 \geq 49

3 + 4 y < 12

\frac{1}{6} \cdot 24

x^{2} + 7 = 0

What is factor (5x+2)^2-(3x-4)^2 ?
The solution to factor (5x+2)^2-(3x-4)^2 is 4(4x-1)(x+3)