What is factor 21c^2+41c+10 ?

The solution to factor 21c^2+41c+10 is (7c+2)(3c+5)

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factor 21c^2+41c+10

factor

21 c^{2} + 41 c + 10

(7 c + 2) (3 c + 5)

Solution steps

21 c^{2} + 41 c + 10

Break the expression into groups

= (21 c^{2} + 6 c) + (35 c + 10)

Factor out

3 c

from

21 c^{2} + 6 c : 3 c (7 c + 2)

Factor out

5

from

35 c + 10 : 5 (7 c + 2)

= 3 c (7 c + 2) + 5 (7 c + 2)

Factor out common term

7 c + 2

= (7 c + 2) (3 c + 5)

3 x + 17 = x

x^{3} \cdot x^{4}

- 130 = - 5 (3 x + 3) + 5

15 = 5 x

∣ 5 x - 5 ∣ - 6 = 13

What is factor 21c^2+41c+10 ?
The solution to factor 21c^2+41c+10 is (7c+2)(3c+5)