What are the solutions to the equation m^2-4m+4=0 ?

The solutions to the equation m^2-4m+4=0 are m=2

Find the zeros of m^2-4m+4=0

The zeros of m^2-4m+4=0 are m=2

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m^{2} - 4 m + 4 = 0

m = 2

Solution steps

m^{2} - 4 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

m_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

m = 2

The solution to the quadratic equation is:

m = 2

\frac{p ^{2} + 5 p - q ^{2} - 5 q}{p - q}

(- 1)^{6}

5 - \frac{x}{4} = \frac{3 x - 2}{6}

450 a^{2} + 242 c^{2} + 660 a c

x (x + 7) = 0

What are the solutions to the equation m^2-4m+4=0 ?
The solutions to the equation m^2-4m+4=0 are m=2
Find the zeros of m^2-4m+4=0
The zeros of m^2-4m+4=0 are m=2