What are the solutions to the equation (x-2)(x+5)=8 ?

The solutions to the equation (x-2)(x+5)=8 are x=3,x=-6

Find the zeros of (x-2)(x+5)=8

The zeros of (x-2)(x+5)=8 are x=3,x=-6

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(x - 2) (x + 5) = 8

x = 3, x = - 6

Solution steps

(x - 2) (x + 5) = 8

Expand

(x - 2) (x + 5) : x^{2} + 3 x - 10

x^{2} + 3 x - 10 = 8

Move

8

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

4.82 y = 156.891

19 > - 4 p - 5

3 k^{2} + 4 k - 4

6 x + 5 = 3 x + 14

\frac{6}{9} = \frac{v}{6}

What are the solutions to the equation (x-2)(x+5)=8 ?
The solutions to the equation (x-2)(x+5)=8 are x=3,x=-6
Find the zeros of (x-2)(x+5)=8
The zeros of (x-2)(x+5)=8 are x=3,x=-6