What is ((a^{-2}b^3)^2)/((a^3b^2)^3) ?

The solution to ((a^{-2}b^3)^2)/((a^3b^2)^3) is 1/(a^{13)}

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simplify ((a^{-2}b^3)^2)/((a^3b^2)^3)

simplify

\frac{( a ^{- 2} b ^{3} ) ^{2}}{( a ^{3} b ^{2} ) ^{3}}

\frac{1}{a ^{13}}

Solution steps

\frac{( a ^{- 2} b ^{3} ) ^{2}}{( a ^{3} b ^{2} ) ^{3}}

Simplify

(a^{- 2} b^{3})^{2} : \frac{b ^{6}}{a ^{4}}

= \frac{\frac{b ^{6}}{a ^{4}}}{( a ^{3} b ^{2} ) ^{3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{b ^{6}}{a ^{4} ( a ^{3} b ^{2} ) ^{3}}

Simplify

a^{4} (a^{3} b^{2})^{3} : a^{13} b^{6}

= \frac{b ^{6}}{a ^{13} b ^{6}}

Cancel the common factor:

b^{6}

= \frac{1}{a ^{13}}

2 (x - 14) - x < 7 (x + 2) + x \leq x + 70

\frac{3}{4} x = 4

\frac{12 x + 65}{( x + 4 ) ^{2}} \geq 5

(\frac{- 2}{2})^{2}

lo g_{3} (- 1)

What is ((a^{-2}b^3)^2)/((a^3b^2)^3) ?
The solution to ((a^{-2}b^3)^2)/((a^3b^2)^3) is 1/(a^{13)}