What are the solutions to the equation -3x^2+6=10 ?

The solutions to the equation -3x^2+6=10 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of -3x^2+6=10

The zeros of -3x^2+6=10 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

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- 3 x^{2} + 6 = 10

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

- 3 x^{2} + 6 = 10

Move

6

to the right side

- 3 x^{2} = 4

Divide both sides by

- 3

x^{2} = - \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{3}, x = - - \frac{4}{3}

- \frac{4}{3} = \frac{2}{3} i

- - \frac{4}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

5 x^{2} + 7 x + 2 = 0

2 ∣ x + 2 ∣ = 4

X + 3 > - 1

6 x^{2} - 6 x - 2 = 0

x^{2} < 0

What are the solutions to the equation -3x^2+6=10 ?
The solutions to the equation -3x^2+6=10 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of -3x^2+6=10
The zeros of -3x^2+6=10 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i