What is (8^{-1}z)/(x^{-1)y^{-1}} ?

The solution to (8^{-1}z)/(x^{-1)y^{-1}} is (zxy)/8

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simplify (8^{-1}z)/(x^{-1)y^{-1}}

simplify

\frac{8 ^{- 1} z}{x ^{- 1} y ^{- 1}}

\frac{z x y}{8}

Solution steps

\frac{8 ^{- 1} z}{x ^{- 1} y ^{- 1}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

8^{- 1} = \frac{1}{8}

= \frac{\frac{1}{8} z}{x ^{- 1} y ^{- 1}}

Simplify

x^{- 1} y^{- 1} : \frac{1}{x y}

= \frac{\frac{1}{8} z}{\frac{1}{x y}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{\frac{1}{8} z x y}{1}

Cancel

\frac{\frac{1}{8} z x y}{1} : \frac{z x y}{8}

= \frac{z x y}{8}

\frac{5 x - 10 y}{x - 2 y}

120 \cdot \frac{150}{150 + 250}

3 = 4 (x - 2) + 5 - 3 x

- 47

- 15 x^{4} y^{2} - 25 x^{3} y^{3}

What is (8^{-1}z)/(x^{-1)y^{-1}} ?
The solution to (8^{-1}z)/(x^{-1)y^{-1}} is (zxy)/8