What are the solutions to the equation 3(y-6)^2=72 ?

The solutions to the equation 3(y-6)^2=72 are y=2sqrt(6)+6,y=-2sqrt(6)+6

Find the zeros of 3(y-6)^2=72

The zeros of 3(y-6)^2=72 are y=2sqrt(6)+6,y=-2sqrt(6)+6

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3 (y - 6)^{2} = 72

y = 26 + 6, y = - 26 + 6

Decimal Notation

y = 10.89897 \dots, y = 1.10102 \dots

Solution steps

3 (y - 6)^{2} = 72

Divide both sides by

3

(y - 6)^{2} = 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 6 = 24 : y = 26 + 6

Solve

y - 6 = - 24 : y = - 26 + 6

The solutions to the quadratic equation are:

y = 26 + 6, y = - 26 + 6

y^{2} = 2 y + 63

2 n^{2} = - 10 n - 7

60 \cdot 6

8^{2} + 8^{2} = c^{2}

\frac{25}{7} = \frac{x}{14}

What are the solutions to the equation 3(y-6)^2=72 ?
The solutions to the equation 3(y-6)^2=72 are y=2sqrt(6)+6,y=-2sqrt(6)+6
Find the zeros of 3(y-6)^2=72
The zeros of 3(y-6)^2=72 are y=2sqrt(6)+6,y=-2sqrt(6)+6