What are the solutions to the equation x^2+(2x)^2=15^2 ?

The solutions to the equation x^2+(2x)^2=15^2 are x=3sqrt(5),x=-3sqrt(5)

Find the zeros of x^2+(2x)^2=15^2

The zeros of x^2+(2x)^2=15^2 are x=3sqrt(5),x=-3sqrt(5)

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x^{2} + (2 x)^{2} = 1 5^{2}

x = 35, x = - 35

Decimal Notation

x = 6.70820 \dots, x = - 6.70820 \dots

Solution steps

x^{2} + (2 x)^{2} = 1 5^{2}

Expand

x^{2} + (2 x)^{2} : 5 x^{2}

Expand

1 5^{2} : 225

5 x^{2} = 225

Move

225

to the left side

5 x^{2} - 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 5 ( - 225 )}{2 \cdot 5}

0^{2} - 4 \cdot 5 (- 225) = 305

x_{1, 2} = \frac{- 0 \pm 30 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 0 + 30 5}{2 \cdot 5}, x_{2} = \frac{- 0 - 30 5}{2 \cdot 5}

x = \frac{- 0 + 30 5}{2 \cdot 5} : 35

x = \frac{- 0 - 30 5}{2 \cdot 5} : - 35

The solutions to the quadratic equation are:

x = 35, x = - 35

\frac{x ^{a}}{x ^{b}}

- 2 x + 5 > 9

0.7 + (3 \cdot t) = 2.5

650

9 x^{7} + 33 x^{3}

What are the solutions to the equation x^2+(2x)^2=15^2 ?
The solutions to the equation x^2+(2x)^2=15^2 are x=3sqrt(5),x=-3sqrt(5)
Find the zeros of x^2+(2x)^2=15^2
The zeros of x^2+(2x)^2=15^2 are x=3sqrt(5),x=-3sqrt(5)