What is 2*2/3*(2/3)^{-3}*(-1/3)^{-1} ?

The solution to 2*2/3*(2/3)^{-3}*(-1/3)^{-1} is -27/2

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simplify 22/3(2/3)^{-3}*(-1/3)^{-1}

simplify

2 \cdot \frac{2}{3} \cdot (\frac{2}{3})^{- 3} \cdot (- \frac{1}{3})^{- 1}

- \frac{27}{2}

Decimal Notation

- 13.5

Solution steps

2 \cdot \frac{2}{3} (\frac{2}{3})^{- 3} (- \frac{1}{3})^{- 1}

\frac{2}{3} (\frac{2}{3})^{- 3} = \frac{1}{\frac{4}{9}}

= 2 \cdot \frac{1}{\frac{4}{9}} (- \frac{1}{3})^{- 1}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 2 \cdot \frac{9}{4} (- \frac{1}{3})^{- 1}

(- \frac{1}{3})^{- 1} = - 3

= 2 (- 3) \frac{9}{4}

Remove parentheses:

(- a) = - a

= - 2 \cdot \frac{9}{4} \cdot 3

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{9 \cdot 2 \cdot 3}{4}

Multiply the numbers:

9 \cdot 2 \cdot 3 = 54

= - \frac{54}{4}

Cancel the common factor:

2

= - \frac{27}{2}

x \geq - 6 - \frac{1}{4} (- 6 x + 5)

1 0^{2} + 2 4^{2} = x^{2}

12 (x + 8) = 11 x - 5

9 v - 2 = 3 v

s^{2} + s + 1 > 0

What is 2*2/3*(2/3)^{-3}*(-1/3)^{-1} ?
The solution to 2*2/3*(2/3)^{-3}*(-1/3)^{-1} is -27/2