What are the solutions to the equation 5m^2-3m=7 ?

The solutions to the equation 5m^2-3m=7 are m=(3+sqrt(149))/(10),m=(3-sqrt(149))/(10)

Find the zeros of 5m^2-3m=7

The zeros of 5m^2-3m=7 are m=(3+sqrt(149))/(10),m=(3-sqrt(149))/(10)

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5 m^{2} - 3 m = 7

m = \frac{3 + 149}{10}, m = \frac{3 - 149}{10}

Decimal Notation

m = 1.52065 \dots, m = - 0.92065 \dots

Solution steps

5 m^{2} - 3 m = 7

Move

7

to the left side

5 m^{2} - 3 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 ( - 7 )}{2 \cdot 5}

(- 3)^{2} - 4 \cdot 5 (- 7) = 149

m_{1, 2} = \frac{- ( - 3 ) \pm 149}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 149}{2 \cdot 5}, m_{2} = \frac{- ( - 3 ) - 149}{2 \cdot 5}

m = \frac{- ( - 3 ) + 149}{2 \cdot 5} : \frac{3 + 149}{10}

m = \frac{- ( - 3 ) - 149}{2 \cdot 5} : \frac{3 - 149}{10}

The solutions to the quadratic equation are:

m = \frac{3 + 149}{10}, m = \frac{3 - 149}{10}

∣ 9 x + 10 ∣ = ∣ x - 13 ∣

4 u^{3} + 5 u^{2} + 12 u + 15

49 n^{2} - 16

\frac{x - 1}{4 x + 5} < \frac{x - 3}{4 x - 3}

- 3 x^{2} - 4 x - 1

What are the solutions to the equation 5m^2-3m=7 ?
The solutions to the equation 5m^2-3m=7 are m=(3+sqrt(149))/(10),m=(3-sqrt(149))/(10)
Find the zeros of 5m^2-3m=7
The zeros of 5m^2-3m=7 are m=(3+sqrt(149))/(10),m=(3-sqrt(149))/(10)