What are the solutions to the equation j^2-17j+72=0 ?

The solutions to the equation j^2-17j+72=0 are j=9,j=8

Find the zeros of j^2-17j+72=0

The zeros of j^2-17j+72=0 are j=9,j=8

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j^{2} - 17 j + 72 = 0

j = 9, j = 8

Solution steps

j^{2} - 17 j + 72 = 0

Solve with the quadratic formula

j_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 72 = 1

j_{1, 2} = \frac{- ( - 17 ) \pm 1}{2 \cdot 1}

Separate the solutions

j_{1} = \frac{- ( - 17 ) + 1}{2 \cdot 1}, j_{2} = \frac{- ( - 17 ) - 1}{2 \cdot 1}

j = \frac{- ( - 17 ) + 1}{2 \cdot 1} : 9

j = \frac{- ( - 17 ) - 1}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

j = 9, j = 8

s^{2} - 1 = 0

(\frac{1}{2} - 10) \div (\frac{2}{3} + \frac{3}{5})

x^{2} + 2 x - 7 = 0

3 x > 9

0.01 \cdot 0.01

What are the solutions to the equation j^2-17j+72=0 ?
The solutions to the equation j^2-17j+72=0 are j=9,j=8
Find the zeros of j^2-17j+72=0
The zeros of j^2-17j+72=0 are j=9,j=8