What are the solutions to the equation 114y^2-49=-186y^2-55 ?

The solutions to the equation 114y^2-49=-186y^2-55 are y= 1/(5sqrt(2))i,y=-1/(5sqrt(2))i

Find the zeros of 114y^2-49=-186y^2-55

The zeros of 114y^2-49=-186y^2-55 are y= 1/(5sqrt(2))i,y=-1/(5sqrt(2))i

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114 y^{2} - 49 = - 186 y^{2} - 55

y = \frac{1}{5 2} i, y = - \frac{1}{5 2} i

Solution steps

114 y^{2} - 49 = - 186 y^{2} - 55

Move

49

to the right side

114 y^{2} = - 186 y^{2} - 6

Move

186 y^{2}

to the left side

300 y^{2} = - 6

Divide both sides by

300

y^{2} = - \frac{1}{50}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{1}{50}, y = - - \frac{1}{50}

- \frac{1}{50} = \frac{1}{5 2} i

- - \frac{1}{50} = - \frac{1}{5 2} i

y = \frac{1}{5 2} i, y = - \frac{1}{5 2} i

\frac{3 - x}{3} = - 2

2 (x + 1) = 3 (x - 1)

(- 6) (- \frac{5}{3})

x^{2} + 3 x + 47 = - 10 x + 7

5 x^{2} + 5 x + 5 = 0

What are the solutions to the equation 114y^2-49=-186y^2-55 ?
The solutions to the equation 114y^2-49=-186y^2-55 are y= 1/(5sqrt(2))i,y=-1/(5sqrt(2))i
Find the zeros of 114y^2-49=-186y^2-55
The zeros of 114y^2-49=-186y^2-55 are y= 1/(5sqrt(2))i,y=-1/(5sqrt(2))i