What are the solutions to the equation (x+2)(2x+3)=6 ?

The solutions to the equation (x+2)(2x+3)=6 are x=0,x=-7/2

Find the zeros of (x+2)(2x+3)=6

The zeros of (x+2)(2x+3)=6 are x=0,x=-7/2

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(x + 2) (2 x + 3) = 6

x = 0, x = - \frac{7}{2}

Decimal Notation

x = 0, x = - 3.5

Solution steps

(x + 2) (2 x + 3) = 6

Expand

(x + 2) (2 x + 3) : 2 x^{2} + 7 x + 6

2 x^{2} + 7 x + 6 = 6

Move

6

to the left side

2 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 2}, x_{2} = \frac{- 7 - 7}{2 \cdot 2}

x = \frac{- 7 + 7}{2 \cdot 2} : 0

x = \frac{- 7 - 7}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{2}

- 9 ∣ m ∣ = - 63

\frac{π}{8} + \frac{π}{8} + \frac{π}{8}

p^{4} - p^{3} q + p q^{3} - q^{4}

8 z + 10 = 2 + 9 z

\frac{3 x ^{2} - 5 x - 2}{x ^{2} - 9} < 0

What are the solutions to the equation (x+2)(2x+3)=6 ?
The solutions to the equation (x+2)(2x+3)=6 are x=0,x=-7/2
Find the zeros of (x+2)(2x+3)=6
The zeros of (x+2)(2x+3)=6 are x=0,x=-7/2