What is expand (a+b)^4 ?

The solution to expand (a+b)^4 is a^4+4a^3b+6a^2b^2+4ab^3+b^4

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expand (a+b)^4

expand

(a + b)^{4}

a^{4} + 4 a^{3} b + 6 a^{2} b^{2} + 4 a b^{3} + b^{4}

Solution steps

(a + b)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = a, b = b

= i = 0 \sum 4 (i 4) a^{(4 - i)} b^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} a^{4} b^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} a^{3} b^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} a^{2} b^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} a^{1} b^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} a^{0} b^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} a^{4} b^{0} : a^{4}

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} a^{3} b^{1} : 4 a^{3} b

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} a^{2} b^{2} : 6 a^{2} b^{2}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} a^{1} b^{3} : 4 a b^{3}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} a^{0} b^{4} : b^{4}

= a^{4} + 4 a^{3} b + 6 a^{2} b^{2} + 4 a b^{3} + b^{4}

8 + \frac{16}{4}

2 w + 8 = 18

∣ 2 x - 3 ∣ = 1

x^{2} + (\frac{1}{2})^{2} = 1^{2}

2 x^{2} - 16 x = - 14

What is expand (a+b)^4 ?
The solution to expand (a+b)^4 is a^4+4a^3b+6a^2b^2+4ab^3+b^4