What are the solutions to the equation (x-2)^2+(0+5)^2=9 ?

The solutions to the equation (x-2)^2+(0+5)^2=9 are x=4i+2,x=-4i+2

Find the zeros of (x-2)^2+(0+5)^2=9

The zeros of (x-2)^2+(0+5)^2=9 are x=4i+2,x=-4i+2

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(x - 2)^{2} + (0 + 5)^{2} = 9

x = 4 i + 2, x = - 4 i + 2

Solution steps

(x - 2)^{2} + (0 + 5)^{2} = 9

Move

(0 + 5)^{2}

to the right side

(x - 2)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 16 : x = 4 i + 2

Solve

x - 2 = - - 16 : x = - 4 i + 2

The solutions to the quadratic equation are:

x = 4 i + 2, x = - 4 i + 2

\frac{1}{4} x^{4} + x^{2} + 1

1 6^{2} + 3 0^{2} = c^{2}

2 k^{2} + 10 k - 5 = 0

4 - 4 m + m^{2}

3 p^{2} q^{2} + 8 p^{4} q^{4} + 7 p^{6} q^{6}

What are the solutions to the equation (x-2)^2+(0+5)^2=9 ?
The solutions to the equation (x-2)^2+(0+5)^2=9 are x=4i+2,x=-4i+2
Find the zeros of (x-2)^2+(0+5)^2=9
The zeros of (x-2)^2+(0+5)^2=9 are x=4i+2,x=-4i+2