What are the solutions to the equation 2x^2-16x=-14 ?

The solutions to the equation 2x^2-16x=-14 are x=7,x=1

Find the zeros of 2x^2-16x=-14

The zeros of 2x^2-16x=-14 are x=7,x=1

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2 x^{2} - 16 x = - 14

x = 7, x = 1

Solution steps

2 x^{2} - 16 x = - 14

Move

14

to the left side

2 x^{2} - 16 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 14 = 12

x_{1, 2} = \frac{- ( - 16 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 12}{2 \cdot 2}

x = \frac{- ( - 16 ) + 12}{2 \cdot 2} : 7

x = \frac{- ( - 16 ) - 12}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

15 x - 82 = 6 x + 152

- 1 < t < 1

∣ x + 8 ∣ - 3 \geq 6

28 (\frac{22}{7.5})

2 x^{2} = - 8 x + 7

What are the solutions to the equation 2x^2-16x=-14 ?
The solutions to the equation 2x^2-16x=-14 are x=7,x=1
Find the zeros of 2x^2-16x=-14
The zeros of 2x^2-16x=-14 are x=7,x=1