What are the solutions to the equation 2x^2=-3 ?

The solutions to the equation 2x^2=-3 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 2x^2=-3

The zeros of 2x^2=-3 are x=sqrt(3/2)i,x=-sqrt(3/2)i

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2 x^{2} = - 3

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

2 x^{2} = - 3

Divide both sides by

2

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

∣ 5 x - 8 ∣ = 16

\frac{1}{2 ^{2}}

x = 0.5 \cdot 0.0005 (- (400000 \cdot x - 5) - 0.8)^{2}

x (8 - 9 x) \leq 0

2 x^{2} + x < 15

What are the solutions to the equation 2x^2=-3 ?
The solutions to the equation 2x^2=-3 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 2x^2=-3
The zeros of 2x^2=-3 are x=sqrt(3/2)i,x=-sqrt(3/2)i