What is the answer to d=sqrt((1-0)^2+(1-0)^2) ?

The answer to d=sqrt((1-0)^2+(1-0)^2) is d=sqrt(2)

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d=sqrt((1-0)^2+(1-0)^2)

d = (1 - 0)^{2} + (1 - 0)^{2}

d = 2

Decimal Notation

d = 1.41421 \dots

Solution steps

d = (1 - 0)^{2} + (1 - 0)^{2}

Simplify

(1 - 0)^{2} + (1 - 0)^{2} : 2

d = 2

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What is the answer to d=sqrt((1-0)^2+(1-0)^2) ?
The answer to d=sqrt((1-0)^2+(1-0)^2) is d=sqrt(2)
Solve for d: d=sqrt((1-0)^2+(1-0)^2)
The solution is d=sqrt(2)