What are the solutions to the equation x(7x-4)=11 ?

The solutions to the equation x(7x-4)=11 are x= 11/7 ,x=-1

Find the zeros of x(7x-4)=11

The zeros of x(7x-4)=11 are x= 11/7 ,x=-1

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x (7 x - 4) = 11

x = \frac{11}{7}, x = - 1

Decimal

x = 1.57142 \dots, x = - 1

Solution steps

x (7 x - 4) = 11

Expand

x (7 x - 4) : 7 x^{2} - 4 x

7 x^{2} - 4 x = 11

Move

11

to the left side

7 x^{2} - 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 ( - 11 )}{2 \cdot 7}

(- 4)^{2} - 4 \cdot 7 (- 11) = 18

x_{1, 2} = \frac{- ( - 4 ) \pm 18}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 18}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 18}{2 \cdot 7}

x = \frac{- ( - 4 ) + 18}{2 \cdot 7} : \frac{11}{7}

x = \frac{- ( - 4 ) - 18}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{11}{7}, x = - 1

6 x^{2} - 7 x + 2 \geq 0

\frac{a ^{2} + b ^{2}}{a ^{3} + b ^{3}} - \frac{1}{a + b}

\frac{5 2 - 6 3}{4 2 - 3 3}

52 \cdot 2

n^{2} - 2 n + 1 = 0

What are the solutions to the equation x(7x-4)=11 ?
The solutions to the equation x(7x-4)=11 are x= 11/7 ,x=-1
Find the zeros of x(7x-4)=11
The zeros of x(7x-4)=11 are x= 11/7 ,x=-1