What are the solutions to the equation b^2-8b-20=0 ?

The solutions to the equation b^2-8b-20=0 are b=10,b=-2

Find the zeros of b^2-8b-20=0

The zeros of b^2-8b-20=0 are b=10,b=-2

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b^{2} - 8 b - 20 = 0

b = 10, b = - 2

Solution steps

b^{2} - 8 b - 20 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

b_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, b_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

b = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

b = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

b = 10, b = - 2

4 x^{2} = 64

8 y (2 y + 7)^{4} - 2 y^{3} (2 y + 7)^{9}

21 y^{2} + 11 y - 2

3 n^{2} + 15 n - 72

c^{2} - 4 c - 12

What are the solutions to the equation b^2-8b-20=0 ?
The solutions to the equation b^2-8b-20=0 are b=10,b=-2
Find the zeros of b^2-8b-20=0
The zeros of b^2-8b-20=0 are b=10,b=-2