What is factor (4y^2+9y-1)-(2y^2+10) ?

The solution to factor (4y^2+9y-1)-(2y^2+10) is (y-1)(2y+11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (4y^2+9y-1)-(2y^2+10)

factor

(4 y^{2} + 9 y - 1) - (2 y^{2} + 10)

(y - 1) (2 y + 11)

Solution steps

(4 y^{2} + 9 y - 1) - (2 y^{2} + 10)

Remove parentheses:

(a) = a

= 4 y^{2} + 9 y - 1 - (2 y^{2} + 10)

- (2 y^{2} + 10) = - 2 (y^{2} + 5)

= 4 y^{2} + 9 y - 1 - 2 (y^{2} + 5)

Expand

- 2 (y^{2} + 5) : - 2 y^{2} - 10

= 4 y^{2} + 9 y - 1 - 2 y^{2} - 10

Simplify

4 y^{2} + 9 y - 1 - 2 y^{2} - 10 : 2 y^{2} + 9 y - 11

= 2 y^{2} + 9 y - 11

Break the expression into groups

= (2 y^{2} - 2 y) + (11 y - 11)

Factor out

2 y

from

2 y^{2} - 2 y : 2 y (y - 1)

Factor out

11

from

11 y - 11 : 11 (y - 1)

= 2 y (y - 1) + 11 (y - 1)

Factor out common term

y - 1

= (y - 1) (2 y + 11)

3 x + 8 = 0

x^{4} + 10 x^{2} + 25

4 (y - 2) - 6 y = - 2 (3 y + 2)

- b + 10 = 4

\frac{x - 4}{2} \geq 6

What is factor (4y^2+9y-1)-(2y^2+10) ?
The solution to factor (4y^2+9y-1)-(2y^2+10) is (y-1)(2y+11)