What are the solutions to the equation 4y^2=196 ?

The solutions to the equation 4y^2=196 are y=7,y=-7

Find the zeros of 4y^2=196

The zeros of 4y^2=196 are y=7,y=-7

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4 y^{2} = 196

y = 7, y = - 7

Solution steps

4 y^{2} = 196

Divide both sides by

4

y^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 49, y = - 49

49 = 7

- 49 = - 7

y = 7, y = - 7

- - 40

∣ 4 x - 3 ∣ = 17

4 c = 64

3 x^{2} + 12 x + 17 = 5

\frac{1}{x} + \frac{1}{1 - x} > 0

What are the solutions to the equation 4y^2=196 ?
The solutions to the equation 4y^2=196 are y=7,y=-7
Find the zeros of 4y^2=196
The zeros of 4y^2=196 are y=7,y=-7