What are the solutions to the equation 5=-1/3 q^2+10 ?

The solutions to the equation 5=-1/3 q^2+10 are q=sqrt(15),q=-sqrt(15)

Find the zeros of 5=-1/3 q^2+10

The zeros of 5=-1/3 q^2+10 are q=sqrt(15),q=-sqrt(15)

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5 = - \frac{1}{3} q^{2} + 10

q = 15, q = - 15

Solution steps

5 = - \frac{1}{3} q^{2} + 10

Switch sides

- \frac{1}{3} q^{2} + 10 = 5

Move

10

to the right side

- \frac{1}{3} q^{2} = - 5

Multiply both sides by

- 3

q^{2} = 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 15, q = - 15

3 x = - 24

∣ 5 x - 3 ∣ = 2

\frac{x}{5} - \frac{1}{2} = \frac{x}{6}

31 - d = 43

\frac{x - 6}{x - 9} \leq 0

What are the solutions to the equation 5=-1/3 q^2+10 ?
The solutions to the equation 5=-1/3 q^2+10 are q=sqrt(15),q=-sqrt(15)
Find the zeros of 5=-1/3 q^2+10
The zeros of 5=-1/3 q^2+10 are q=sqrt(15),q=-sqrt(15)