What are the solutions to the equation -4x^2+16x=21 ?

The solutions to the equation -4x^2+16x=21 are x=2-i(sqrt(5))/2 ,x=2+i(sqrt(5))/2

Find the zeros of -4x^2+16x=21

The zeros of -4x^2+16x=21 are x=2-i(sqrt(5))/2 ,x=2+i(sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 16 x = 21

x = 2 - i \frac{5}{2}, x = 2 + i \frac{5}{2}

Solution steps

- 4 x^{2} + 16 x = 21

Move

21

to the left side

- 4 x^{2} + 16 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) ( - 21 )}{2 ( - 4 )}

Simplify

1 6^{2} - 4 (- 4) (- 21) : 45 i

x_{1, 2} = \frac{- 16 \pm 4 5 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 5 i}{2 ( - 4 )}, x_{2} = \frac{- 16 - 4 5 i}{2 ( - 4 )}

x = \frac{- 16 + 4 5 i}{2 ( - 4 )} : 2 - i \frac{5}{2}

x = \frac{- 16 - 4 5 i}{2 ( - 4 )} : 2 + i \frac{5}{2}

The solutions to the quadratic equation are:

x = 2 - i \frac{5}{2}, x = 2 + i \frac{5}{2}

\frac{1 ^{2}}{2}

\frac{7 a + 3}{6} = \frac{a + 5}{2}

\frac{x}{5} - \frac{2 x - 5}{3} = \frac{3}{4}

x^{2} + 10 - 21 = 0

4 - 2 x = x - 5

What are the solutions to the equation -4x^2+16x=21 ?
The solutions to the equation -4x^2+16x=21 are x=2-i(sqrt(5))/2 ,x=2+i(sqrt(5))/2
Find the zeros of -4x^2+16x=21
The zeros of -4x^2+16x=21 are x=2-i(sqrt(5))/2 ,x=2+i(sqrt(5))/2