What are the solutions to the equation 4r^2-25r=21 ?

The solutions to the equation 4r^2-25r=21 are r=7,r=-3/4

Find the zeros of 4r^2-25r=21

The zeros of 4r^2-25r=21 are r=7,r=-3/4

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4 r^{2} - 25 r = 21

r = 7, r = - \frac{3}{4}

Solution steps

4 r^{2} - 25 r = 21

Move

21

to the left side

4 r^{2} - 25 r - 21 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 4 ( - 21 )}{2 \cdot 4}

(- 25)^{2} - 4 \cdot 4 (- 21) = 31

r_{1, 2} = \frac{- ( - 25 ) \pm 31}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 25 ) + 31}{2 \cdot 4}, r_{2} = \frac{- ( - 25 ) - 31}{2 \cdot 4}

r = \frac{- ( - 25 ) + 31}{2 \cdot 4} : 7

r = \frac{- ( - 25 ) - 31}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

r = 7, r = - \frac{3}{4}

(2 a^{2} b) (4 a b^{2})

3 < x - 3 < 7

152

9 y^{2} + 12 y + 4

∣ 2 x + 1 ∣ > 2

What are the solutions to the equation 4r^2-25r=21 ?
The solutions to the equation 4r^2-25r=21 are r=7,r=-3/4
Find the zeros of 4r^2-25r=21
The zeros of 4r^2-25r=21 are r=7,r=-3/4