What are the solutions to the equation 35x^2+120x=-45 ?

The solutions to the equation 35x^2+120x=-45 are x=-3/7 ,x=-3

Find the zeros of 35x^2+120x=-45

The zeros of 35x^2+120x=-45 are x=-3/7 ,x=-3

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35 x^{2} + 120 x = - 45

x = - \frac{3}{7}, x = - 3

Solution steps

35 x^{2} + 120 x = - 45

Move

45

to the left side

35 x^{2} + 120 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 35 \cdot 45}{2 \cdot 35}

12 0^{2} - 4 \cdot 35 \cdot 45 = 90

x_{1, 2} = \frac{- 120 \pm 90}{2 \cdot 35}

Separate the solutions

x_{1} = \frac{- 120 + 90}{2 \cdot 35}, x_{2} = \frac{- 120 - 90}{2 \cdot 35}

x = \frac{- 120 + 90}{2 \cdot 35} : - \frac{3}{7}

x = \frac{- 120 - 90}{2 \cdot 35} : - 3

The solutions to the quadratic equation are:

x = - \frac{3}{7}, x = - 3

64 - 9

- 14 x + 23 = 14 x - 23

\frac{x + 1}{2 x ^{2} - x - 1} \geq 0

∣ x + 5 ∣ \geq 2 x

36 = 25 + u

What are the solutions to the equation 35x^2+120x=-45 ?
The solutions to the equation 35x^2+120x=-45 are x=-3/7 ,x=-3
Find the zeros of 35x^2+120x=-45
The zeros of 35x^2+120x=-45 are x=-3/7 ,x=-3