What is 10-(((x-15))/3)^29<x<= 24 ?

The solution to 10-(((x-15))/3)^29<x<= 24 is x<= 24

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10-(((x-15))/3)^29<x<= 24

10 - (\frac{( x - 15 )}{3})^{2} 9 < x \leq 24

x \leq 24

Solution steps

10 - (\frac{( x - 15 )}{3})^{2} \cdot 9 < x \leq 24

a < u \leq b

then

a < u and u \leq b

10 - (\frac{( x - 15 )}{3})^{2} \cdot 9 < x and x \leq 24

10 - (\frac{x - 15}{3})^{2} \cdot 9 < x :

True for all

x

Combine the intervals

True for all x and x \leq 24

Merge Overlapping Intervals

x \leq 24

- 2 a - 4 = - 8

a^{2} - 11 a + 18

lo g_{16} (64)

x - 5 > 17

- 4 (x + 4) = 3 (x + 4) + 7

What is 10-(((x-15))/3)^29<x<= 24 ?
The solution to 10-(((x-15))/3)^29<x<= 24 is x<= 24