What are the solutions to the equation r^2-2r+1=0 ?

The solutions to the equation r^2-2r+1=0 are r=1

Find the zeros of r^2-2r+1=0

The zeros of r^2-2r+1=0 are r=1

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r^{2} - 2 r + 1 = 0

r = 1

Solution steps

r^{2} - 2 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

r_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

r = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

r = 1

The solution to the quadratic equation is:

r = 1

64 - x^{3}

5 x^{2} + 5 x - 3 = 0

4 k^{3} - 7 k^{2} - 16 k + 28

2 s^{2} + 7 s + 5

3 x^{2} + 5 < 53

What are the solutions to the equation r^2-2r+1=0 ?
The solutions to the equation r^2-2r+1=0 are r=1
Find the zeros of r^2-2r+1=0
The zeros of r^2-2r+1=0 are r=1