What are the solutions to the equation 3x^2+24x+55=7 ?

The solutions to the equation 3x^2+24x+55=7 are x=-4

Find the zeros of 3x^2+24x+55=7

The zeros of 3x^2+24x+55=7 are x=-4

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3 x^{2} + 24 x + 55 = 7

x = - 4

Solution steps

3 x^{2} + 24 x + 55 = 7

Move

7

to the left side

3 x^{2} + 24 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 48 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 3}

x = \frac{- 24}{2 \cdot 3}

\frac{- 24}{2 \cdot 3} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

3 (x - 10) = - 9

20 - 3 x = 15

- 0.9 x^{2} + 1.7 x + 2.5 = 0

9 k + 7 \geq 10 k - 1

4 x^{2} + 4 x + 1

What are the solutions to the equation 3x^2+24x+55=7 ?
The solutions to the equation 3x^2+24x+55=7 are x=-4
Find the zeros of 3x^2+24x+55=7
The zeros of 3x^2+24x+55=7 are x=-4