What is the answer to (8x-2)(3x+4)=(4x+3)(6x-1) ?

The answer to (8x-2)(3x+4)=(4x+3)(6x-1) is x= 5/12

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(8x-2)(3x+4)=(4x+3)(6x-1)

(8 x - 2) (3 x + 4) = (4 x + 3) (6 x - 1)

x = \frac{5}{12}

Solution steps

(8 x - 2) (3 x + 4) = (4 x + 3) (6 x - 1)

Expand

(8 x - 2) (3 x + 4) : 24 x^{2} + 26 x - 8

Expand

(4 x + 3) (6 x - 1) : 24 x^{2} + 14 x - 3

24 x^{2} + 26 x - 8 = 24 x^{2} + 14 x - 3

Move

8

to the right side

24 x^{2} + 26 x = 24 x^{2} + 14 x + 5

Subtract

24 x^{2} + 14 x

from both sides

24 x^{2} + 26 x - (24 x^{2} + 14 x) = 24 x^{2} + 14 x + 5 - (24 x^{2} + 14 x)

Simplify

12 x = 5

Divide both sides by

12

x = \frac{5}{12}

x^{2} - x + 1 = 9

7 + 4 ∣ 5 x - 8 ∣ = 15

c = 3 0^{2} + 1 8^{2}

(\frac{8}{6})^{2}

\frac{2}{4} \cdot \frac{1}{2}

What is the answer to (8x-2)(3x+4)=(4x+3)(6x-1) ?
The answer to (8x-2)(3x+4)=(4x+3)(6x-1) is x= 5/12
Solve for x: (8x-2)(3x+4)=(4x+3)(6x-1)
The solution is x= 5/12