What is 8y-3>10\lor 8y-3<10 ?

The solution to 8y-3>10\lor 8y-3 13/8

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8y-3>10\lor 8y-3<10

8 y - 3 > 10 or 8 y - 3 < 10

y < \frac{13}{8} or y > \frac{13}{8}

Solution steps

8 y - 3 > 10 or 8 y - 3 < 10

8 y - 3 > 10 : y > \frac{13}{8}

8 y - 3 < 10 : y < \frac{13}{8}

Combine the intervals

y > \frac{13}{8} or y < \frac{13}{8}

Merge Overlapping Intervals

y < \frac{13}{8} or y > \frac{13}{8}

v = (3)^{2} + 2 (3)

x^{2} < x

\frac{1}{1 - \frac{1}{2}}

20 = 8 t + \frac{2 t ^{2}}{2}

a^{\frac{1}{2}} \cdot a^{\frac{1}{2}}

What is 8y-3>10\lor 8y-3<10 ?
The solution to 8y-3>10\lor 8y-3<10 is y< 13/8 \lor y> 13/8