What are the solutions to the equation 8x^2+16x-68=3 ?

The solutions to the equation 8x^2+16x-68=3 are x=(-4+sqrt(158))/4 ,x=-(4+sqrt(158))/4

Find the zeros of 8x^2+16x-68=3

The zeros of 8x^2+16x-68=3 are x=(-4+sqrt(158))/4 ,x=-(4+sqrt(158))/4

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8 x^{2} + 16 x - 68 = 3

x = \frac{- 4 + 158}{4}, x = - \frac{4 + 158}{4}

Decimal Notation

x = 2.14245 \dots, x = - 4.14245 \dots

Solution steps

8 x^{2} + 16 x - 68 = 3

Move

3

to the left side

8 x^{2} + 16 x - 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 ( - 71 )}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 (- 71) = 4158

x_{1, 2} = \frac{- 16 \pm 4 158}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 16 + 4 158}{2 \cdot 8}, x_{2} = \frac{- 16 - 4 158}{2 \cdot 8}

x = \frac{- 16 + 4 158}{2 \cdot 8} : \frac{- 4 + 158}{4}

x = \frac{- 16 - 4 158}{2 \cdot 8} : - \frac{4 + 158}{4}

The solutions to the quadratic equation are:

x = \frac{- 4 + 158}{4}, x = - \frac{4 + 158}{4}

\frac{3}{4} x = 12

9 (y - 5) = - 9

\frac{2 x}{x - 2} \geq 1

- 25 + 21 + (- 4) + 25

8 x + 40

What are the solutions to the equation 8x^2+16x-68=3 ?
The solutions to the equation 8x^2+16x-68=3 are x=(-4+sqrt(158))/4 ,x=-(4+sqrt(158))/4
Find the zeros of 8x^2+16x-68=3
The zeros of 8x^2+16x-68=3 are x=(-4+sqrt(158))/4 ,x=-(4+sqrt(158))/4