What are the solutions to the equation 104^2=x^2+(x+56)^2 ?

The solutions to the equation 104^2=x^2+(x+56)^2 are x=40,x=-96

Find the zeros of 104^2=x^2+(x+56)^2

The zeros of 104^2=x^2+(x+56)^2 are x=40,x=-96

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10 4^{2} = x^{2} + (x + 56)^{2}

x = 40, x = - 96

Solution steps

10 4^{2} = x^{2} + (x + 56)^{2}

Expand

10 4^{2} : 10816

Expand

x^{2} + (x + 56)^{2} : 2 x^{2} + 112 x + 3136

10816 = 2 x^{2} + 112 x + 3136

Switch sides

2 x^{2} + 112 x + 3136 = 10816

Move

10816

to the left side

2 x^{2} + 112 x - 7680 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 \cdot 2 ( - 7680 )}{2 \cdot 2}

11 2^{2} - 4 \cdot 2 (- 7680) = 272

x_{1, 2} = \frac{- 112 \pm 272}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 112 + 272}{2 \cdot 2}, x_{2} = \frac{- 112 - 272}{2 \cdot 2}

x = \frac{- 112 + 272}{2 \cdot 2} : 40

x = \frac{- 112 - 272}{2 \cdot 2} : - 96

The solutions to the quadratic equation are:

x = 40, x = - 96

x^{4} + 3 x^{2} - 4 = 0

- 6 ∣ 5 - x ∣ < - 30

5 x^{2} + 6 x = - 2

x^{3} + 6 x^{2} - 19 x - 24

5 x^{2} + 20 x + 32 = 0

What are the solutions to the equation 104^2=x^2+(x+56)^2 ?
The solutions to the equation 104^2=x^2+(x+56)^2 are x=40,x=-96
Find the zeros of 104^2=x^2+(x+56)^2
The zeros of 104^2=x^2+(x+56)^2 are x=40,x=-96