What are the solutions to the equation -x^2+18=93 ?

The solutions to the equation -x^2+18=93 are x=sqrt(3)*5i,x=-sqrt(3)*5i

Find the zeros of -x^2+18=93

The zeros of -x^2+18=93 are x=sqrt(3)*5i,x=-sqrt(3)*5i

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- x^{2} + 18 = 93

x = 3 \cdot 5 i, x = - 3 \cdot 5 i

Solution steps

- x^{2} + 18 = 93

Move

18

to the right side

- x^{2} = 75

Divide both sides by

- 1

x^{2} = - 75

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 75, x = - - 75

- 75 = 3 \cdot 5 i

- - 75 = - 3 \cdot 5 i

x = 3 \cdot 5 i, x = - 3 \cdot 5 i

\frac{5}{6} - \frac{4}{8}

2 x^{2} - 8 x + 5 = 0

- 12 x^{4} + 32 x^{3} - 15 x^{2} - 3 x + 2

\frac{3}{5} x - \frac{7}{5} x + \frac{5}{3} = \frac{31}{15}

(- \frac{3}{5})^{3}

What are the solutions to the equation -x^2+18=93 ?
The solutions to the equation -x^2+18=93 are x=sqrt(3)*5i,x=-sqrt(3)*5i
Find the zeros of -x^2+18=93
The zeros of -x^2+18=93 are x=sqrt(3)*5i,x=-sqrt(3)*5i