What are the solutions to the equation 4x-x^2=0 ?

The solutions to the equation 4x-x^2=0 are x=0,x=4

Find the zeros of 4x-x^2=0

The zeros of 4x-x^2=0 are x=0,x=4

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4 x - x^{2} = 0

x = 0, x = 4

Solution steps

4 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4}{2 ( - 1 )}

x = \frac{- 4 + 4}{2 ( - 1 )} : 0

x = \frac{- 4 - 4}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

5 x^{2} - 6 x = 8

2 x^{2} + x = 55

0 = - 16 t^{2} + 16 t + 192

1 2^{2} + 1 2^{2} = c^{2}

1 < ∣ x - 2 ∣ < 4

What are the solutions to the equation 4x-x^2=0 ?
The solutions to the equation 4x-x^2=0 are x=0,x=4
Find the zeros of 4x-x^2=0
The zeros of 4x-x^2=0 are x=0,x=4