What are the solutions to the equation 6x^2-2x=7 ?

The solutions to the equation 6x^2-2x=7 are x=(1+sqrt(43))/6 ,x=(1-sqrt(43))/6

Find the zeros of 6x^2-2x=7

The zeros of 6x^2-2x=7 are x=(1+sqrt(43))/6 ,x=(1-sqrt(43))/6

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6 x^{2} - 2 x = 7

x = \frac{1 + 43}{6}, x = \frac{1 - 43}{6}

Decimal Notation

x = 1.25957 \dots, x = - 0.92623 \dots

Solution steps

6 x^{2} - 2 x = 7

Move

7

to the left side

6 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 2)^{2} - 4 \cdot 6 (- 7) = 243

x_{1, 2} = \frac{- ( - 2 ) \pm 2 43}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 43}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 43}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 43}{2 \cdot 6} : \frac{1 + 43}{6}

x = \frac{- ( - 2 ) - 2 43}{2 \cdot 6} : \frac{1 - 43}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 43}{6}, x = \frac{1 - 43}{6}

y^{2} + 8 y + 17 = 0

2 y^{2} = 4 - y^{2}

- 2 (x^{2} - x - 3) = 6 x

5 x - 7 \leq 7 x - 11 \leq 5 x + 9

(\frac{4}{49})^{\frac{3}{2}}

What are the solutions to the equation 6x^2-2x=7 ?
The solutions to the equation 6x^2-2x=7 are x=(1+sqrt(43))/6 ,x=(1-sqrt(43))/6
Find the zeros of 6x^2-2x=7
The zeros of 6x^2-2x=7 are x=(1+sqrt(43))/6 ,x=(1-sqrt(43))/6