What are the solutions to the equation y^2+8y+17=0 ?

The solutions to the equation y^2+8y+17=0 are y=-4+i,y=-4-i

Find the zeros of y^2+8y+17=0

The zeros of y^2+8y+17=0 are y=-4+i,y=-4-i

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y^{2} + 8 y + 17 = 0

y = - 4 + i, y = - 4 - i

Solution steps

y^{2} + 8 y + 17 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 17 : 2 i

y_{1, 2} = \frac{- 8 \pm 2 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 2 i}{2 \cdot 1}, y_{2} = \frac{- 8 - 2 i}{2 \cdot 1}

y = \frac{- 8 + 2 i}{2 \cdot 1} : - 4 + i

y = \frac{- 8 - 2 i}{2 \cdot 1} : - 4 - i

The solutions to the quadratic equation are:

y = - 4 + i, y = - 4 - i

2 y^{2} = 4 - y^{2}

- 2 (x^{2} - x - 3) = 6 x

5 x - 7 \leq 7 x - 11 \leq 5 x + 9

0 = - 16 x^{2} + 20 x

x + 8 + ∣ 4 - x ∣ = 0

What are the solutions to the equation y^2+8y+17=0 ?
The solutions to the equation y^2+8y+17=0 are y=-4+i,y=-4-i
Find the zeros of y^2+8y+17=0
The zeros of y^2+8y+17=0 are y=-4+i,y=-4-i