What are the solutions to the equation (12a)(11a-1)=0 ?

The solutions to the equation (12a)(11a-1)=0 are a=0,a= 1/11

Find the zeros of (12a)(11a-1)=0

The zeros of (12a)(11a-1)=0 are a=0,a= 1/11

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(12 a) (11 a - 1) = 0

a = 0, a = \frac{1}{11}

Solution steps

(12 a) (11 a - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

12 a = 0 or 11 a - 1 = 0

Solve

12 a = 0 : a = 0

Solve

11 a - 1 = 0 : a = \frac{1}{11}

The solutions to the quadratic equation are:

a = 0, a = \frac{1}{11}

y^{2} + 9 - 6 y - 4 x^{2}

2.8 + 3.2 x + 1 = 16.6

∣ 3 x + 2 ∣ \geq 4

\frac{x + 4}{x + 7} < 2

∣ 5 x - 5 ∣ < 15

What are the solutions to the equation (12a)(11a-1)=0 ?
The solutions to the equation (12a)(11a-1)=0 are a=0,a= 1/11
Find the zeros of (12a)(11a-1)=0
The zeros of (12a)(11a-1)=0 are a=0,a= 1/11