What are the solutions to the equation (3x+5)^2-39=-22 ?

The solutions to the equation (3x+5)^2-39=-22 are x=(sqrt(17)-5)/3 ,x=(-sqrt(17)-5)/3

Find the zeros of (3x+5)^2-39=-22

The zeros of (3x+5)^2-39=-22 are x=(sqrt(17)-5)/3 ,x=(-sqrt(17)-5)/3

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(3 x + 5)^{2} - 39 = - 22

x = \frac{17 - 5}{3}, x = \frac{- 17 - 5}{3}

Decimal Notation

x = - 0.29229 \dots, x = - 3.04103 \dots

Solution steps

(3 x + 5)^{2} - 39 = - 22

Move

39

to the right side

(3 x + 5)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 5 = 17 : x = \frac{17 - 5}{3}

Solve

3 x + 5 = - 17 : x = \frac{- 17 - 5}{3}

The solutions to the quadratic equation are:

x = \frac{17 - 5}{3}, x = \frac{- 17 - 5}{3}

3 m^{- 4}

\frac{3}{5} (x - 6) = \frac{2}{3} (3 x - 5)

\frac{( ( x + y ) ( e x yy ) - e x y ( 1 ) )}{( x + y ) ^{2}}

5 x - 4 \geq 12

\frac{1}{0.0004}

What are the solutions to the equation (3x+5)^2-39=-22 ?
The solutions to the equation (3x+5)^2-39=-22 are x=(sqrt(17)-5)/3 ,x=(-sqrt(17)-5)/3
Find the zeros of (3x+5)^2-39=-22
The zeros of (3x+5)^2-39=-22 are x=(sqrt(17)-5)/3 ,x=(-sqrt(17)-5)/3