What are the solutions to the equation s^2-9s+18=0 ?

The solutions to the equation s^2-9s+18=0 are s=6,s=3

Find the zeros of s^2-9s+18=0

The zeros of s^2-9s+18=0 are s=6,s=3

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s^{2} - 9 s + 18 = 0

s = 6, s = 3

Solution steps

s^{2} - 9 s + 18 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

s_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, s_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

s = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

s = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

s = 6, s = 3

∣ 3 x - 4 ∣ = 8

\frac{- 10}{7}

- 15 \leq 5 v

5 x^{2} - x - 6 = 0

3 \cdot (m - 4) - n \cdot (m - 4)

What are the solutions to the equation s^2-9s+18=0 ?
The solutions to the equation s^2-9s+18=0 are s=6,s=3
Find the zeros of s^2-9s+18=0
The zeros of s^2-9s+18=0 are s=6,s=3