What is (6^3*20^2*125)/(25^2*2^3*12^2) ?

The solution to (6^3*20^2*125)/(25^2*2^3*12^2) is 15

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simplify (6^320^2125)/(25^22^312^2)

simplify

\frac{6 ^{3} \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 2 ^{3} \cdot 1 2 ^{2}}

15

Solution steps

\frac{6 ^{3} \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 2 ^{3} \cdot 1 2 ^{2}}

Factor

6^{3} : 2^{3} \cdot 3^{3}

= \frac{2 ^{3} \cdot 3 ^{3} \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 2 ^{3} \cdot 1 2 ^{2}}

Cancel the common factor:

2^{3}

= \frac{3 ^{3} \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 1 2 ^{2}}

Factor

1 2^{2} : 3^{2} \cdot 4^{2}

= \frac{3 ^{3} \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 3 ^{2} \cdot 4 ^{2}}

\frac{3 ^{3}}{3 ^{2}} = 3

= \frac{3 \cdot 2 0 ^{2} \cdot 125}{2 5 ^{2} \cdot 4 ^{2}}

Factor

2 0^{2} : 5^{2} \cdot 4^{2}

= \frac{3 \cdot 5 ^{2} \cdot 4 ^{2} \cdot 125}{2 5 ^{2} \cdot 4 ^{2}}

Factor

2 5^{2} : 5^{4}

= \frac{3 \cdot 5 ^{2} \cdot 4 ^{2} \cdot 125}{5 ^{4} \cdot 4 ^{2}}

\frac{5 ^{2}}{5 ^{4}} = \frac{1}{5 ^{2}}

= \frac{3 \cdot 4 ^{2} \cdot 125}{5 ^{2} \cdot 4 ^{2}}

Cancel the common factor:

4^{2}

= \frac{3 \cdot 125}{5 ^{2}}

Factor the number:

125 = 5^{3}

= \frac{3 \cdot 5 ^{3}}{5 ^{2}}

\frac{5 ^{3}}{5 ^{2}} = 5

= 3 \cdot 5

Multiply the numbers:

3 \cdot 5 = 15

= 15

- 104 = 8 x

5 x = 25

(7 + 5 i) (- 6 + 9 i)

(\frac{6}{17})^{9 x}

5 x^{3} - 45 x^{2} + 70 x

What is (6^3*20^2*125)/(25^2*2^3*12^2) ?
The solution to (6^3*20^2*125)/(25^2*2^3*12^2) is 15