What is -(x-1)^5(x+1)^3<= 0 ?

The solution to -(x-1)^5(x+1)^3 = 1

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-(x-1)^5(x+1)^3<= 0

- (x - 1)^{5} (x + 1)^{3} \leq 0

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

- (x - 1)^{5} (x + 1)^{3} \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1)^{5} (x + 1)^{3}) (- 1) \geq 0 \cdot (- 1)

Simplify

(x - 1)^{5} (x + 1)^{3} \geq 0

Identify the intervals

x \leq - 1 or x \geq 1

\frac{y}{8} + 19 = 30

- 5 (- x - 4) - 3 x - 5 = 13

3 x + 2 = 2 + 3 x

- - 48

- \frac{42}{6}

What is -(x-1)^5(x+1)^3<= 0 ?
The solution to -(x-1)^5(x+1)^3<= 0 is x<=-1\lor x>= 1