What are the solutions to the equation 2x^2-4=7x ?

The solutions to the equation 2x^2-4=7x are x=4,x=-1/2

Find the zeros of 2x^2-4=7x

The zeros of 2x^2-4=7x are x=4,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 4 = 7 x

x = 4, x = - \frac{1}{2}

Solution steps

2 x^{2} - 4 = 7 x

Move

7 x

to the left side

2 x^{2} - 4 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

x = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

x = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{2}

lo g_{8} (\frac{1}{64})

\frac{- 30}{8}

4 x = - 16

0 = x^{2} + 3 x - 4

4 x^{2} + 20 x + 13 = 0

What are the solutions to the equation 2x^2-4=7x ?
The solutions to the equation 2x^2-4=7x are x=4,x=-1/2
Find the zeros of 2x^2-4=7x
The zeros of 2x^2-4=7x are x=4,x=-1/2